x^2-7x+10=(x-5)(x+2)

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Solution for x^2-7x+10=(x-5)(x+2) equation: 



x^2-7x+10=(x-5)(x+2)

We move all terms to the left:

x^2-7x+10-((x-5)(x+2))=0

We multiply parentheses ..

x^2-((+x^2+2x-5x-10))-7x+10=0



We calculate terms in parentheses: -((+x^2+2x-5x-10)), so:

(+x^2+2x-5x-10)

We get rid of parentheses

x^2+2x-5x-10

We add all the numbers together, and all the variables

x^2-3x-10

Back to the equation:

-(x^2-3x-10)



We add all the numbers together, and all the variables

x^2-7x-(x^2-3x-10)+10=0

We get rid of parentheses

x^2-x^2-7x+3x+10+10=0

We add all the numbers together, and all the variables

-4x+20=0

We move all terms containing x to the left, all other terms to the right

-4x=-20

x=-20/-4

x=+5

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